Solve this riddle......poor little snail...!!!!?

A snail is at the bottom of a well and wants to get out. He manages to crawl up the wall 3 feet each day, but at night he must rest ( after all that work during the day ) and so he slips back down 2 feet. If the well is 30 feet deep, How long will it take him to get out?

Answer

28 days.
on the 27th day it would get to 29 but slip down to 27.
then on the 28th day it would get to the top and wouldnt slip back down.

Answer2

Depends on how you look at it. Does it have to climb 30 feet to get out or above 30?
If 30 feet is enough it will get out on the 27th day, if it has to reach above 30 feet it will get out on the 28th day. Why? Because on day 26 it will crawl up to 29 feet then at night slide back to 27. The next day it will crawl 3 feet again and thus reach 30 feet. (just add one day if it has to reach above 30 feet)

1 foot/day until the last move, that takes it out, in which it will move 3 feet without sliding back down.

Answer3

It will come out on 28th day - By crawling 3 feet up during day time and slipping 2 feet down during night, it will be up by 1 feet each day. Thus in 27 days it will reach 27 feet and when it clims further 3 feet on the 28th day during day time, it will reach out of the well and even if it go for rest - it will not fell down. Therefore the answer is 28 days.

Answer4

Thirty days.
If he climbs three, falls two, then technically he's only climbing one. So, one foot a day for thirty feet.
Thirty days. c:

Answer5

It is 30 'cause ,each day he will climb 1 feet [ 3 - 2 ] for the well who is 30 feet.

Answer6

27 days

Answer7

30 days

Answer8

27 Days. On the last day he makes it to the top.

Answer9

30 DAYS!

Answer10

30 days!!!! am I right?

Answer11

a month?